Mason is preparing for an endurance running competition. On Friday, he ran 15 3/5 miles. On Saturday, he ran twice as much as he did on Friday. On Sunday, he ran 3 3/4 less than he did on Saturday. How many miles did Mason run for three days?

Respuesta :

he ran for 34 and 19/20 miles

Answer:

[tex]74 \frac{5}{20}[/tex]

Step-by-step explanation:

On Friday, he ran [tex]15\frac{3}{5}[/tex]  miles.

converting mix number to fraction we get,

[tex]15\frac{3}{5}[/tex] =[tex]\frac{75+3}{5}[/tex] =[tex]\frac{78}{5}[/tex]


On Saturday, he ran twice as much as he did on Friday.

so, for Saturday it is,

2 x  [tex] \frac{78}{5} [/tex]  miles

=[tex]\frac{78 x 2}{5}[/tex]

=[tex]\frac{156}{5}[/tex]


On Sunday he ran [tex]3\frac{3}{4}[/tex] less than Saturday.

[tex]3\frac{3}{4}[/tex]=[tex]\frac{12+3}{4}[/tex] =[tex]\frac{15}{4}[/tex]

So, for Sunday it is-

[tex]\frac{156}{5}[/tex] - [tex] \frac{15}{4}[/tex]

=[tex]\frac{156x4-15x5}{20}[/tex]

=[tex]\frac{624-75}{20}[/tex]

=[tex]\frac{549}{20}[/tex]


So, for three days,

total distance would be-

[tex]\frac{78}{5}[/tex] + [tex]\frac{156}{5}[/tex] + [tex]\frac{549}{20}[/tex]

=[tex]\frac{78x4 + 156x4 + 549}{20}[/tex]

=[tex]\frac{312+624+549}{20}[/tex]

=[tex]\frac{1485}{20}[/tex]

=[tex]74 \frac{5}{20}[/tex]


So, Mason ran  [tex]74 \frac{5}{20}[/tex]  miles in three days.

ACCESS MORE