Hey there!
[tex]24[/tex] → [tex]24[/tex]
"Greater than" → [tex]>[/tex]
[tex]-3h[/tex] → [tex]-3h[/tex]
"Greater than or equal to"→ [tex]\geq[/tex]
[tex]-9[/tex] →[tex]-9[/tex]
Now, that we highlighted our key terms , we could now solve our problem (or at least what we're working with)
Answer: [tex]24 >[/tex] [tex]-3h[/tex] [tex]\geq -9[/tex] (this is what we get if we translated our equation)
But, if we're looking for the value of the "unknown number" ([tex]h[/tex]) , then let's work on it
So, first we have to divide all of your numbers by a negative 3 ( [tex]-3[/tex])
[tex]\frac{24}{-3}[/tex] [tex]>[/tex] [tex]\frac{-3h}{3}[/tex] [tex]\frac{-9}{3}[/tex]
Cancel: [tex]\frac{-3h}{-3}[/tex]
Keep1: [tex]\frac{24}{-3}[/tex]
Keep2: [tex]\frac{-9}{-3 }[/tex]
[tex]\frac{24}{-3}[/tex] [tex]= -8[/tex]
[tex]\frac{-9}{-3}[/tex] [tex]= 3[/tex]
Therefore for that part of the answer should look like this: [tex]-8 <[/tex] [tex]h[/tex] [tex]\leq[/tex] [tex]3[/tex]
Good luck on your assignment and enjoy your day!
~[tex]LoveYourselfFirst:)[/tex]