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gmany

[tex]24 > -3h\geq-9\qquad|\text{change the signs}\\\\-24 < 3h\leq9\qquad|\text{divide both sides by 3}\\\\-8 < h\leq3[/tex]

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Hey there!

[tex]24[/tex] → [tex]24[/tex]

"Greater than"  → [tex]>[/tex]

[tex]-3h[/tex]  → [tex]-3h[/tex]

"Greater than or equal to"→ [tex]\geq[/tex]

[tex]-9[/tex] →[tex]-9[/tex]

Now, that we highlighted our key terms , we could now solve our problem (or at least what we're working with)

Answer: [tex]24 >[/tex] [tex]-3h[/tex] [tex]\geq -9[/tex] (this is what we get if we translated our equation)

But, if we're looking for the value of the "unknown number" ([tex]h[/tex]) , then let's work on it

So, first we have to divide all of your numbers by a negative 3 ( [tex]-3[/tex])

[tex]\frac{24}{-3}[/tex] [tex]>[/tex] [tex]\frac{-3h}{3}[/tex] [tex]\frac{-9}{3}[/tex]

Cancel: [tex]\frac{-3h}{-3}[/tex]

Keep1: [tex]\frac{24}{-3}[/tex]

Keep2: [tex]\frac{-9}{-3 }[/tex]

[tex]\frac{24}{-3}[/tex] [tex]= -8[/tex]

[tex]\frac{-9}{-3}[/tex] [tex]= 3[/tex]

Therefore for that part of the answer should look like this: [tex]-8 <[/tex] [tex]h[/tex] [tex]\leq[/tex] [tex]3[/tex]

Good luck on your assignment and enjoy your day!

~[tex]LoveYourselfFirst:)[/tex]

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