Question

What function is increasing?

A. F(x)=6^x
B. F(x)=(0.6)^x
C. F(x)=(1/60)^x
D. F(x)=(1/6)^x

Answer 1

$y=a^x$

The function is increasing if a > 0.

The function is decreasing if 0 < a < 1.

Therefore your answer is

$A.\ f(x)=6^x$

$6^x\to a=6 > 1\\(0.6)^x\to a=0.6 < 1\\\left(\dfrac{1}{60}\right)^x\to a=\dfrac{1}{60} < 1\\\\\left(\dfrac{1}{6}\right)^x\to a=\dfrac{1}{6} < 1$