Respuesta :
This is a particular case, but it is not necessarily true. If triangles STU and XYZ are similar, the corresponding sides are in the same proportion. So, there exists a number [tex] k \in \mathbb{R} [/tex] such that
[tex] ST = kXY,\quad TU=kYZ,\quad SU=kXZ [/tex]
So, if [tex] k=1 [/tex], the corresponding sides are actually congruent, but it can be any other number. For example, if [tex] k=2 [/tex], triangle XYZ is exactly twice as large as triangle STU, but they are still similar.
