Question

The distance d in feet that a dropped object falls in t seconds is given by the equation d÷16=t2. How long does it take a dropped object to fall 64 feet

Answer 1

aight so you have to solve for t
first you plug in for d
$(64) \div 16 = t2$
solve this
$4 = t2$
now you must divide by two to get t by itself
$\frac{4}{2} = \frac{t2}{2}$
solve this and your solution is
$t = 2$
or 2 seconds

Answer 2

Answer:

It takes 2 seconds.

Step-by-step explanation:

Consider the provided equation.

$d\div 16=t^2$

The provided equation can be written as

$\frac{d}{16}=t^2$

We need to calculate how long does it take a dropped object to fall 64 feet.

Substitute the d=64 in above equation and solve the equation for t.

$\frac{64}16}=t^2$

$4=t^2$

$t=\pm2$

Here, time should be positive so ignore the negative value of t.

$t=2$

Hence, it takes 2 seconds.