Question

A right hexagonal pyramid has a base with an area of 42 in2. The height of the pyramid is 9 inches. What is the volume of the pyramid? 63 in3 4.7 in3 21 in3 126 in3


NEED ANSWER ASAP

Answer 1

126 in³

the volume of a pyramid = $\frac{1}{3}$ × area of base × height

thus V = $\frac{1}{3}$ × 42 × 9 = 126 in³