1.2 L sample of gas is determined to contain 0.5 moles of nitrogen. At the same temperature and pressure, how many moles of gas would there be in a 20 L sample?

Respuesta :

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A 20 L sample of the gas contains 8.3 mol N₂.

According to Avogadro’s Law, if p and T are constant

V₂/V₁ = n₂/n

n₂ = n₁ × V₂/V

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n₁ = 0.5 mol; V₁ = 1.2 L

n₂ = ?;           V₂ = 20 L

n₂ = 0.5 mol × (20 L/1.2 L) = 8.3 mol