Question

A bag contains 1 blue, 2 green, 3 yellow, and 3 red marbles, as shown. What is the probability of drawing a red marble out of the bag without looking?

Answer 1

$|\Omega|=1+2+3+3=9\\|A|=3\\\\P(A)=\dfrac{3}{9}=\dfrac{1}{3}\approx33\%$

Answer 2

The probability of drawing a red marble out of the bag without looking is 1/3

Probability is the likelihood or chance that an event will occur

Probability = expected outcome/total outcome

If a bag contains 1 blue, 2 green, 3 yellow, and 3 red marbles, the total outcome will be;

Total outcome = 1 + 2 + 3 + 3 = 9 marbles

If  a red marble out of the bag without looking, the expected outcome is 3

Pr(drawing a red marble) = 3/9 = 1/3

Hence the probability of drawing a red marble out of the bag without looking is 1/3

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