Question

A gas with constant temperature has a pressure of 4 atm this pressure changes to 0.2 atm causing the volume to increase to 500L what was the initial volume of the gas

Answer 1

Using the combined gas law of P1V1=P2V2 and plug it in you get (4)V1 for you don't have initial volume = (0.2)(500) --> 4V1=100, divide by the coefficient on both sides and you get V1=25

Answer 2

Answer:

$25L$

Explanation:

The problem can be solved using Boyle's law for the volume and pressure of a gas at constant temperature:

$P_{1}V_{1}=P_{2}V_{2}$

Where the quantities with sub-index 1 are the initial conditions for the gas and the quantities with sub-index 2 are for the final conditions of the gas.

We want to know the initial volume, this is:

$V_{1}=\frac{P_{2}V_{2}}{P_{1}}$

we also know from the problem that

$P_{1}=4atm\\P_{2}=0.2atm\\V_{2}=500L$

Thus, the initial volume V1 is:

$V_{1}=\frac{0.2atm*500L}{4atm}$

$V_{1}=25L$