Question

simplify radical √m^4 n^7

answers

-mn^2 √n
-m^2n^2 √n
-m^2n^3 √n

Answer 1

 $\sqrt{m^{4} n^{7} }$

= $\sqrt{m*m*m*m*m*N*N*N*N*N*N*N}$

Look for groups of 2 (a group of two on the inside, makes one on the outside)

= $m*m*N*N*N\sqrt{N}$

= $m^{2} n^{3} \sqrt{n}$

Answer: C