What is the slope of the line on the graph?



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$\text{Basic}$
$x$y$x^2$\sqrt{ }$\frac{x}{ }$x\frac{ }{ }$x^{ }$x_{ }$\degree$\left(\right)$\abs{ }$\pi$\infty$
A coordinate grid that includes the line y equals six x minus one. Points are plotted at begin ordered pair 1 comma 5 end ordered pair begin ordered pair 0 comma negative 1end ordered pair and begin ordered pair negative 1 comma negative 7 end ordered pair.

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Answer:

Slope = 6

Step-by-step explanation:

Reading your description carefully, the equation of line has been given to be

[tex]y=6x-1[/tex]

When we compare this with the standard form of a straight line

[tex]y=mx+c[/tex]

We immediately see that the slope or gradient m = 6.

Alternatively, when we consider the coordinates of the points mentioned, we have

(1, 5)    ;     (0, -1)     ;     (-1, -7)

We can take any two points out of these three and calculate the slope using the formula

[tex]m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

For example, let us consider the points (1, 5) and (-1, -7)

Here x₁ = 1; x₂ = -1 and y₁ = 5; y₂ = -7

Plugging the numbers in the above formula, we have

[tex]m=\frac{(-7)-(5)}{(-1)-(1)}[/tex]

[tex]m=\frac{-12}{-2} =6[/tex]

This agrees with what we calculated directly from the equation of the line!

Hence, slope of the line on the graph = 6

Answer:

its 6

Step-by-step explanation: