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Equation of a line in slope-intercept form is y = mx + b

If it has a slope of 1/2, you set m = 1/2. If it has a y-int at the origin, you set b = 0

Put it all together:

y = 1/2x + 0

or

y = 1/2x

Linear equation with slope [tex]\frac{1}{2}[/tex] and y-intercept as origin will be [tex]y=\frac{1}{2}x[/tex].

    Equation of a line with slope 'm' and y-intercept 'b' is given by the equation,

  • y = mx + b

It's given in the question,

  • Slope of the line 'm' = [tex]\frac{1}{2}[/tex]
  • y-intercept of the line → Origin or (0, 0)

If the line passes through origin, line will have no y-intercept (b = 0)

By substituting the values of 'm' and 'b' in the equation,

[tex]y=\frac{1}{2}x+0[/tex]

[tex]y=\frac{1}{2}x[/tex]

    Therefore, linear equation will be [tex]y=\frac{1}{2}x[/tex].

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