Question

what is the square root of 28x to the third power y to the third power

Answer 1

Hello!

√28x³y³ is equal to $2xy\sqrt{7xy}$

We can find this solution through the following steps.

1. Rewriting the equation by factoring 4 from 28, factoring out x², and factoring out y²
2. We then can rewrite 4 as 2² in our equation, leaving us with $\sqrt{2^{2}*7*(x^{2}x)*y^{2}y }$
3. We will then move our x and 7, and rewrite $2^{2}*x^{2}* y^{2}$ as $(2xy)^{2}$
4. We can then pull the terms from the radical leaving us with $2xy\sqrt{7xy}$