The answer is B : F = 1.8 X 10 ∧ -15
Given:
Velocity of the proton: 2.0 × 10∧6 m/sec
Magnetic field strength(B): 5.5 × 10∧-3 tesla
Now it is given that velocity and the magnetic field are at 90 degree.
Also Magnetic force F= qvBsin∅
where F is the magnetic force
q is the charge of the proton which is equal to 1.602x10∧-19 coloumbs
∅ is the angle between the v and B.
v is the velocity of the proton
B is the magnetic field
Substituting the values we get
F = 1.602 x 10 ∧-19 × 2.0 × 10∧6 × 5.5 × 10∧-3 Sin 90
F= 17.6 x 10 ∧-16 N
F= 1.76 x 10∧-15 N
Rounding off we get F = 1.8 X 10 ∧ -15 N
