Question

value of 3x^2 +4y^2 if x=2, y=1, and z= -3

Answer 1

$3x^2+4y^2\\\\\text{Put the values of x=2, y=1 and z=-3 to the expression:}\\\\3(2^2)+4(1^2)=3(4)+4(1)=12+4=16$