Question

Given: AO = OD
OB = OC
m∠1=74˚, m∠2=36˚
Find: m∠ACD

Answer 1

First of all m<1 + m<2 = m<ACD

Soo we just need to add them.

74 + 36 = 110

So m<ACD = 110 degrees.

GOOD LUCK! :)

Answer 2

Answer:

$m\angle ACD=110^{\circ}$

Step-by-step explanation:

Given information: AO = OD, OB = OC, m∠1=74˚, m∠2=36˚.

In triangle OAB and ODC,

$AO=OD$                              (Given)

$m\angle AOB=m\angle DOC$             (Vertical angles)

$OB=OC$                              (Given)

By SAS postulate,

$\triangle OAB\cong \triangle ODC$

$\angle OBA\cong \triangle OCD$             (CPCTC)

$m\angle OBA=m\triangle OCD$

$74^{\circ}=m\triangle OCD$

From the given figure it is clear that

$\angle ACD=\angle ACO+\angle OCD$

$\angle ACD=36^{\circ}+74^{\circ}$

$\angle ACD=110^{\circ}$

Therefore, the measure of angle ACD is 110°.