Given
A laboratory technician needs to make a 117-liter batch of a 20% acid solution.
How much the technician combine an acid solution that is pure acid with another that is 10% to get the desired concentration.
To proof
let us assume that the solution that is pure acid = x liters
let us assume that the anthor solution that is 10% = y liters
Than
the equation becomes
x + y = 117
As given in the question
technician needs to make a 117-liter batch of a 20% acid solution
laboratory technician combine an acid solution that is pure acid with another that is 10% to get the desired concentration
Convert 20% in the simpler form
[tex]=\frac{20}{100}[/tex]
= 0.2
Convert 10% in the simpler form
[tex]=\frac{10}{100}[/tex]
= 0.1
Than the equation becomes
0.2 × 117 = x + 0.1y
234 = 10x + y
Than the two equation are
x + y = 117
234 = 10x + y
subtracted x + y = 117 from 234 = 10x + y
10x+y -x -y = 234 -117
9x = 117
x= 13
put this in the equation x + y = 117
13 + y =117
y = 117 - 13
y = 104
Therefore
The solution that is pure acid be 13 liters.
than the other solution that is 10% is 104 liters.
Hence proved