Question

please help!! Find three consecutive odd integers that have an average of 13. please explain

Answer 1

11, 13 and 15

note that consecutive odd integers have a difference of 2 between them

example : 1, 3 , 5

let the 3 consecutive integers be n , n+ 2, n + 4

The sum of the 3 integers divided by 3 gives the average, thus

$\frac{n + n + 2 + n + 4}{3}$ = 13

$\frac{3n + 6}{3}$= 13 (multiply both sides by 3 to eliminate fraction )

3n + 6 = 3 × 13 = 39 ( subtract 6 from both sides )

3n = 39 - 6 = 33 ( divide both sides by 3 )

n = $\frac{33}{3}$ = 11

the integers are 11, 11 + 2, 11 + 4 = 11, 13, 15