Question

The formula of a salt is XCl2. The X-ion in this salt has 28 electrons. The metal X is

Answer 1

X ion has lost 2 electrons and become X+2 the total electron of metal X ion is 28 then   x metal should be having 30 electron in its metallic state,  that mean the metal with atomic N0-30 and its is Zinc

Answer 2

Answer : The metal X is, zinc (Zn)

Explanation :

The formula of a salt is, $XCl_2$

First we have to determine the oxidation state of metal 'X'.

Let the oxidation state of metal 'X' be, 'a'.

The oxidation state of chlorine atom is, (-1).

So,

$a+2(-1)=0\\\\a-2=0\\\\a=+2$

Now we have to determine the atomic number of metal 'X'.

As we are given that,

Number of electrons of X-ion = 28

And, there are (+2) charge present in X-ion that means 2 electrons are removed from the electrons of X-ion.

So, the number of electrons present in metal X = 28 + 2 = 30

Atomic number = Number of electrons = 30

Thus, the element that has 30 electrons or atomic number 30 will be zinc metal.

Hence, the metal X is, zinc