Question

A normal walking speed is around 2.0 m/s . how much time t does it take the box to reach this speed if it has the acceleration 5.54 m/s2 that you calculated above?

Answer 1

Given:

u(initial velocity)=0

a=5.54m/s^2

v(final velocity)=2 m/s

v=u +at

Where v is the final velocity.

u is the initial velocity

a is the acceleration.

t is the time

2=0+5.54t

t=2/5.54

t=0.36 sec