We have that for the Question "Calculate the activation energy for the reaction" it can be said that The activation energy is
From the question we are told
Generally the equation for the Activation energy is mathematically given as
[tex]10(\frac{kr}{ki})=\frac{Ea}{2.303R}(\frac{1}{t_1}-\frac{1}{t_2}})\\\\Therefore\\\\10(\frac{0.0815}{0.0796})=\frac{Ea}{2.303*8.314}(\frac{1}{1010}-\frac{1}{1220}})\\\\Ea=\frac{0.01024}{8.9*10^{-6}}/mol\\\\[/tex]
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