Question

A human lung at maximum capacity has a volume of 3.0 liters. If the partial pressure of oxygen in the air is 21.1 kilopascals and the air temperature is 295 K, how many moles of oxygen are in the lung?

Answer 1

V = maximum capacity of human lung = 3 liter = 3 x 0.001 m³ = 0.003 m³      (Since 1 liter = 0.001 m³)

P = pressure of oxygen = 21.1 kilo pascal = 21.1 x 1000 = 21100 Pa      (since 1 kilo = 1000)

T = temperature of air = 295 K

n = number of moles of oxygen

Using the ideal gas equation

PV = n RT

inserting the above values in the equation

(21100) (0.003) = n (8.314) (295)

n = 0.026 moles

Answer 2

A. 0.026 mol

#platofam.