-110 = 13 + 3(4h -6) . . . . . . given
-110 = 13 + 12h -18 . . . . . . . eliminate parentheses using the distributive property
-110 = 12h -5 . . . . . . . . . . . . collect terms
-105 = 12h . . . . . . . . . . . . . . add 5 to both sides of the equation
-105/12 = h = -8.75
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There are many ways you can solve this. Another is to undo the operations done to h. The variable h is ...
- multiplied by 4
- has -6 added to the product
- has the sum multiplied by 3
- has 13 added to the product
When you undo these, you do it in reverse order:
-110 -13 = 3(4h -6) . . . . subtract 13
-123/3 = 4h -6 . . . . . . . divide by 3
-41 +6 = 4h . . . . . . . . . .add 6
-35/4 = h . . . . . . . . . . . divide by 4
h = -8.75
