Question

Factor the expression over the complex numbers. x2+18 Enter your answer in the box.

Answer 1

( x - 3i√2)(x + 3i√2)

solve x² + 18 = 0

x² = - 18 ⇒ x = ±√- 18 = ±3i√2

factors are ( x - (3i√2))(x - (-3i√2))

x² + 18 = (x - 3i√2)(x + 3i√2)

Answer 2

Answer:

Factor of the expression x²+18 over the complex numbers is:

(x-i3√2)(x+i3√2)

Step-by-step explanation:

x²+18=0

⇒ x²= -18

⇒ x=±√(-18)

⇒ x=±i3√2

⇒ (x-i3√2)(x+i3√2)=0

Hence, factor of the expression x²+18 over the complex numbers is:

(x-i3√2)(x+i3√2)