Question

Which values of p and q result in an equation with no solutions? -68x+ p=qx+34.

Answer 1

-68x + p = qx + 34

p - 34 = qx + 68x    added 68x to both sides & subtracted 34 from both sides.

p - 34 = x(q + 68)

$\frac{p - 34}{q + 68} = x$

The denominator cannot be equal to zero so q + 68 ≠ 0   ⇒   q ≠ -68

You didn't upload the options but look for the one that has q = -68.