Question

Write An equation in slope intercept form for the line passing through each pair of points (-1,3) and (2,-5)

Answer 1

Slope m = y2-y1/x2-x1

Points (-1,3) and (2,-5)

M= -5-3/2-(-1)

M= -8/3

M= -8/3

Slope is -8/3

Now fill in the formula equation of a line using one if the points and slope to find b .

(2,-5) and slope -8/3

Y=mx+b

-5=-8/3(2)+b

-5=-16/3+b

-5+16/3=b

1/3=b

Now put all together

Y= -8/3x+1/3

Answer 2

Slope intercept form of a line is y = mx + b, where m is the slope and b is the y coordinate of the y intercept.

The easiest way to solve this problem is by using another equation for a line, also known as point slope form. This equation is best to use for a line if you have  a point and slope of the line, but do not have the y-intercept.

We need to find the slope of this line passing through the pair of points (-1, 3) and (2, -5). We can do this by using the slope formula: $\frac{y_2-y_1}{x_2-x_1}$. Substitute in the appropriate coordinates.

$\frac{-5-3}{2-(-1)}$ = $\frac{-8}{3}$, so the slope of the line is -8/3.

Point slope form of a line is $y-y_1=m(x-x_1)$. Substitute -8/3 for m, and use the point coordinate (-1, 3) for y1 and x1. You could use either point coordinate but I chose to use this one.

$y-3= -8/3[x-(-1)]$

Distribute -8/3 inside the parentheses.

$y-3= -8/3x - 8/3$

Add 3 to both sides.

y = -8/3x + 1/3 is your answer (slope intercept form).