kharrizyanderson kharrizyanderson

01-10-2018
Physics

contestada

A stone is thrown upward and reaches a maximum height of 45.0 m above its launch point what was the speed with which the stone was thrown

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Jacquiriva Jacquiriva

01-10-2018

V(f) ^2 = v(I)^2 + 2adeltay
0^2 = v(I)^2 + 2(-9.8)(45)
V(I) = 30 m/s

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