Answer:- 8.35 kJ
Solution:- It asks to calculate the heat required to melt 25 g of ice at 0 degree C. It is a phase change and the heat energy is calculated by using the formula:
[tex]q=m\Delta H_f_u_s[/tex]
where q is the heat energy, m is the mass and [tex]\Delta H_f_u_s[/tex] is the enthalpy of fusion of ice. Enthalpy of fusion of ice is 334 Joule per gram.
Let's plug in the given values in the formula:
[tex]q=25g*\frac{334J}{g}[/tex]
q = 8350 J
since, 1000 = 1 kJ
So, [tex]8350J(\frac{1kJ}{1000J})[/tex]
= 8.35 kJ
So, 8.35 kJ of heat is required to melt 25 g of ice at 0 degree C.