Question

A car is driving at a velocity of 24 m/s. If its brakes can supply an acceleration of -5.0 m/s2, how much time will be required to bring the car to a stop?

Answer 1

in equation form it reads: 0=24-5x
You can isolate the variable by subtracting 24 from both sides to get -24=5x.
Now all that has to be done is divide both sides by -5, which will result in -4.8=x

Answer 2

Answer:

Time, t = 4.8 seconds

Explanation:

Given that,

Initial velocity of the car, u = 24 m/s

Acceleration of the car, $a=-5\ m/s^2$

When the brakes are applied, v = 0

Let t is the time required by the car to stop it. It can be calculated using the formula of the acceleration as :

$a=\dfrac{v-u}{t}$

$t=\dfrac{v-u}{a}$

$t=\dfrac{0-24}{-5}$

t = 4.8 seconds

So, the time required to bring the car to a stop is 4.8 seconds. Hence, this is the required solution.