Question

the average number of points a basketball team scored for three games was 63 points. In two games, they scored the same number of points, which was 6 points more than they scored in the third game. Write and solve an equation to find the number of points they scored in each game.

Answer 1

The points for the three games are x, x, and y. There are two x's because two games had the same score.

$\frac{2x+y}{3}$ = 63 (the equation for getting average)

x = y + 6

Now just plug one into the other equation: $\frac{2(y + 6) + y}{3}$ = 63

$\frac{3y + 12}{3}$ = 63

y + 4 = 63

y = 63 - 4 = 59 so x = y + 6 = 59 + 6 = 65

Answer: scores are 59, 65, 65

Answer 2

The numbers are 59, 65 and 65.

Let the points for the 3 games be represented by x, x and y

Therefore, the equation to solve the average will be:

(x+x+y)/3 = 63

(2x + y) / 3 = 63

Cross multiply

2x + y = 63 × 3

2x + y = 189 ...... i

Note that x = y + 6 ..... ii

Put the value of x into equation i

2x + y = 189

2(y + 6) + y = 189

2y + 12 + y = 189

Collect like terms

3y = 189 - 12

3y = 177

y = 177/3

y = 59

Therefore, x = y + 6 = 59 + 6 = 65

The numbers are 59, 65 and 65.

Read related link on:

https://brainly.com/question/24429956