Question

Determine the Kelvin temperature required for 0.0470 mol of gas to fill a balloon to 1.20L under 0.988 atm pressure. a. 306K c. 308K b. 307K d. 320K

Answer 1

here it is worked out

Answer 2

The Kelvin temperature required is 307 K. The correct answer is b. 307K

Ideal gas equation

From the question, we are to determine the Kelvin temperature required to the gas to fill the balloon

From the ideal gas equation,

PV = nRT

Then, we can write that

$T = \frac{PV}{nR}$

Where T is the temperature in Kelvin

P is the pressure

V is the volume

n is the number of moles

and R is the gas constant (R = 0.08206 L.atm.K⁻¹.mol⁻¹)

From the given information,

P = 0.988 atm

V = 1.20 L

n = 0.0470 mol

Putting the parameters into the equation, we get

$T = \frac{0.988 \times 1.20}{0.0470 \times 0.08206}$

$T = \frac{1.1856}{0.00385682}$

T = 307.4035 K

T ≅ 307 K

Hence, the Kelvin temperature required is 307 K. The correct answer is b. 307K

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