The y terms in table 1 are: 2, 10, 26, 50, 82, 122
The change in y, or the increase in y, is +8, +16, +24, +32, +40
The new sequence {8,16,24,32,40} has each term increase by 8. This second difference being constant indicates we have a quadratic function that is not linear. So table 1 is not linear.
Table 2's y values are: 2, 17, 13, 9, 5, 1
The terms start to increase but then decrease after that first increase. This inconsistency means we don't have a linear function. Table 2 is not linear.
Table 3 is linear and the function rule is: y = -4x+29
If we plug in x = 2, then we get y = -4(2)+29 = -8+29 = 21
If we plug in x = 3, we get y = -4(3)+29 = -12+29 = 17
and so on...
Each time x increases by 1, the y terms decrease by 4, therefore the slope is -4. To find the y intercept, plug in any point from the table, say (x,y) = (2,21) and then solve for b. I'm referencing the slope intercept equation y = mx+b with m = -4 as the slope.