tam52 tam52
  • 29-09-2018
  • Mathematics
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3-2i/5+i
[tex]3 - 2i \div 5 + i [/tex]

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Аноним Аноним
  • 29-09-2018

[tex]3-2i/5+i[/tex]

[tex]\frac{3*5+(-2)*1)+(-2*5-3*1)i}{5^2+1^2}[/tex]

[tex]\frac{13-13i}{26}=\frac{1-i}{2}[/tex]

[tex]=\frac{1}{2}-\frac{1}{2}i[/tex]

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-Charlie

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