Height of the hotel room is given as
[tex]H = 228 m[/tex]
now as it falls freely from the top
its initial speed is given as
[tex]v_i = 0[/tex]
also the acceleration is given as
[tex]a = g = 9.8 m/s^2[/tex]
now we will use kinematics here
[tex]d = v_i*t + \frac{1}{2}at^2[/tex]
[tex]228 = 0 + \frac{1}{2}*9.8*t^2[/tex]
[tex]228 = 4.9 t^2[/tex]
[tex]t^2 = 46.53[/tex]
[tex]t = 6.82 s[/tex]
so it will take t = 6.82 s to reach the bottom