Respuesta :

To solve this quadratic, use factoring:

[tex]x^{2}-11x+19=-5[/tex] add 5 to both sides

[tex]x^{2} -11x+24=0[/tex] factor this into two binomials using factors 3 and 8 for 24

(x-3)(x-8)=0  for this to be a true statement either the first binomial factor or the second binomial factor must equal '0'..

so x=3 and x=8


gmany

[tex]x^2-11x+19=-5\ \ \ \ |+5\\\\x^2-11x+24=0\\\\\text{find such a and b for which}\ a+b=-11\ \text{and}\ ab=24\\a=-8\ \text{and}\ b=-3\\\\x^2-8x-3x+24=0\\\\x(x-8)-3(x-8)=0\\\\(x-8)(x-3)+0\iff x-8=0\ \vee\ x-3=0\\\\\boxed{x=8\ \vee\ x=3}[/tex]

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