Question

If ƒ( x ) = x 2 + 1 and g( x ) = 3 x + 1, find 2ƒ(1) + 3g(4).

Answer 1

$f(x)=x^2+1,\ g(x)=3x+1\\\\f(1)-\text{put 1 instead of x}\\\\f(1)=1^2+1=1+1=2\\\\g(4)-\text{put 4 instead of x}\\\\g(4)=3(4)+1=12+1=13\\\\2f(1)+3g(4)=2(2)+3(13)=4+39=43$

$Answer:\ 2f(1)+3g(4)=43$