The base angles of isosceles PQR are equal,
Hence,
[tex]2x -18°=5y-8°[/tex]
[tex]2x-5y=-8°+18° [/tex]
[tex]2x-5y=10° \: .....(1)[/tex]
Sum of interior angles is 180°
[tex](x+41°)+(2x-18°)+(5y-8°)=180° [/tex]
[tex]3x+5y+15°=180° [/tex]
[tex]3x+5y=165° \: ...(2)[/tex]
Equation (2)+(1) gives
[tex]5x=175° [/tex]
Divide through by 5.
[tex]x=35°[/tex]
Substitute x=35° in equation (1)
[tex]2(35°)-5y=10°[/tex]
[tex] - 5y=10° - 70 \degree[/tex]
[tex] - 5y= - 60° [/tex]
Divide through by -5.
[tex] y=12° [/tex]
