[tex]f(x)=4x-1\\\\g(x)=2x-\dfrac{1}{3}\\\\f(2)\to\text{put x=2 to the equation of the function f}\\\\f(2)=4(2)-1=8-1=7\\\\g(f(2))=g(7)\to\text{put x=7 to the equation of the function g}\\\\g(7)=2(7)-\dfrac{1}{3}=14-\dfrac{1}{3}=13\dfrac{2}{3}\\\\Answer:\ g(f(2))=13\dfrac{2}{3}[/tex]
