Question

The average height of an apple tree is 4.00 m how long will it take an apple falling from that high to reach the ground given G equals -9.8 m/s squared

Answer 1

Answer

The time will be 0.9 sec

Explanation

According to the question

Distance apple will cover = 4 m

Gravitational acceleration = 9.8 m/s2

As we know

$S=1/2 at^2$

In vertical direction a = g

By rearranging

$T = \sqrt{(2s/g)}$

$Time = \sqrt{(2 * 4/9.8)}$

$Time = 0.9 sec$

So, apple will take the time of 0.9s