[tex]\text{Answer} : \text{The expected value of a t-shirt is \$31.}[/tex]
Explanation:
Since we have given that
The prices of three t-shirts styles i.e $24, $30, $36 with their probability is given by
[tex]\frac{1}{6}, \frac{1}{2},\frac{1}{3}[/tex]
As we know that,
[tex]E(X)= \sum_{1}^{3}x_iP(x_i)[/tex]
[tex]\text{where} x_i \text{ is the prices of t- shirts styles}[/tex]
Now,
[tex]x_1= \$24 , x_2=\$30 , x_3=$36[/tex]
and
[tex]P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}[/tex]
So,
[tex]E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31[/tex]
So, the expected value of a t-shirt = $31.