Question

The herbology garden is rectangular with a perimeter of 32 feet. The length of the garden is 4 feet less than three times the width. Find the length of the garden. Enter a number only as your answer.

Answer 1

The perimeter formula here is P = 2W + 2L.

In this situation   P = 32 ft = 2(3W-4) + 2W, or   32 ft = 6W - 8 + 2W, or

                                                                             32 ft = 8W - 8.

Solve this for W by adding 8 to both sides of the equation:

40 ft = 8W.    Then W = 5 ft, and L = 3(5 ft) - 4 ft = 11 ft.

Note that P = 2(5 ft) + 2(11 ft) comes out to (10 + 22) ft, or 32 ft, as was given.

Answer 2

The length of the garden is 11 feet.

What is a Perimeter of Rectangle?

• Perimeter is the sum of the length of all the sides of the geometric figure.
• Rectangle has 4 sides with 2 lengths and 2 breadths.
• Perimeter of rectangle = 2(Length + Breadth)

Given: For a herbology rectangular garden.

Perimeter = 32 feet

Let the length of a garden be x.

Let the breadth of a garden be y.

According to the given condition:

x = 3y - 4

also, perimeter will be given by:

2(x + y) = 32

⇒ x + y = 16

⇒ y = 16 - x

Now, put the equation y = 16 - x in equation x = 3y - 4, we get:

⇒ x = 3y - 4

⇒ x = 3(16 - x) - 4

⇒ x = 48 - 3x - 4

⇒ x + 3x = 44

⇒ 4x = 44

⇒ x = 11 feet

Therefore, the length of the rectangular herbology garden is 11 feet.

Learn more about the Perimeter of Rectangle here: https://brainly.com/question/18296182

#SPJ2