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What is the potential difference across a 2.0-ohm resistor that draws 2.0 coulombs of charge per second

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AL2006

Potential difference ('voltage') = (resistance) x (current)

Current = charge/time

Current in this one = (2 coulombs/sec) = 2 Amperes

Potential difference = (2 ohms) x (2 Amperes)

Potential difference = 4 volts

The potential difference across a 2.0-ohm resistor that draws 2.0 coulombs of charge per second will be V=4 volts

What is potential difference?

Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit.

The potential difference (which is the same as voltage) is equal to the amount of current multiplied by the resistance.

A potential difference of one Volt is equal to one Joule of energy being used by one Coulomb of charge when it flows between two points in a circuit.

The formula for potential difference is :

V=iR

[tex]V=\dfrac{Q}{t}{R}[/tex]

Here the charge Q=2C In t=1 Sec and R=2 Ohm

[tex]V=\dfrac{2}{1}\times {2}[/tex]

V=4 Volts

Hence the potential difference across a 2.0-ohm resistor that draws 2.0 coulombs of charge per second will be V=4 volts

To know more about Potential difference follow

https://brainly.com/question/25923373

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