Question

an object is fired from the ground at 200 meters per second at an angle of 30* with the horizontal

a.calculate the horizontal and vertical components of the initial velocity

b. after 6.0 seconds how far has the object traveled on the horizontal direction

c. how high is the object at this point

Answer 1

Horizontal component = V cos(30°) = V (√3/2) = 73.2 m/s

Vertical component = V sin(30°) = V (0.5) = 100 m/s

In 6 seconds, the object travels horizontally (173.2 m/s x 6 sec) = 1,039 m

After 6 seconds, the object's height above the ground is

H = V₀t + 1/2 a t²

H = (100 m/s)(6 s) + (1/2) (-9.8 m/s²) (6 s)²

H = (600 m) - (4.9 m/s²) (36 s²)

H = (600 m) - (176.4 m)

Height = 423.6 m