Question

A ski lift takes a 60 kg skier to the top of a 100 m slope. Assuming her skis are frictionless, what is her speed when she gets to the bottom of the slope?

Answer 1

The Answer is: v=44.27 m/s

So basically we need to find the speed in this problem! Gravitational Potential Energy becomes Kinetic energy since she is going down a slope. The Formula for GPE is GPE=mgh and the formula for KE is KE=1/2mv^2.

m is mass, g is gravity, h is height and v is velocity (speed).

So...

GPE=KE

mgh=1/2mv^2

To Solve for V we need to get v on one side.

v=√2gh

Then Plug in the values!

g= 9.8 (It's always 9.8 if the problem doesn't say)

h= 100m

So...

v=√2(9.8)(100)

v=44.27 m/s!

Answer 2

The speed of the skier when she gets to the bottom of the slope is equal to 44.27 m/s.

Given the following data:

Mass = 60 kg.

Height of slope = 100 meters.

How to calculate the speed.

In accordance with the law of conservation of energy, the potential energy possessed by the skier at the top is equal to the kinetic energy possessed by the skier at the bottom of the ski:

$P.E=K.E\\\\mgh = \frac{1}{2}mv^2\\\\gh= \frac{1}{2} v^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2 \times 9.8 \times 100}$

v = 44.27 m/s.

Read more on kinetic energy here: brainly.com/question/1242059