dudehi78 dudehi78
  • 28-09-2018
  • Mathematics
contestada

find the value of b so that 4x^2+bx+9 has a factor of 2x-3

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tramserran
tramserran tramserran
  • 28-09-2018

          2x - 3          

2x - 3 (4x² + bx + 9

        - (4x² - 6x)

               (b + 6)x  + 9

            -      (-6x   + 9)      

(b + 6)x - (-6x) = 0    it must equal zero if 2x - 3 is a factor  

bx + 6x + 6x = 0

bx + 12x = 0

        bx = -12x    

          b  = -12

Answer: b = -12

You can check by multiplying (2x - 3) the factor given and (2x - 3) the factor found when dividing by the given factor.

(2x - 3)(2x - 3) = 4x² -12x + 9

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