Question

what is the value of b so that the equation x^2+bx+5=0 will have x intercepts (-5,0) and (-1,0)

Answer 1

plug one intercepts: (-1)^2+(-1)b+5=0
(-5)^2+(-5)b+5=0
simplify: 6-b=0
30-5b=0
solve for b: 6=b
30/5=b