f(x)=4-x^2 and g(x)=6x
find (g -f)(3)
We know (g - f)(x) = g(x) - f(x)
(g -f)(3) = g(3) - f(3)
LEts find g(3)
we know g(x) = 6x . so g(3) = 6(3) = 18
We know [tex]f(x) = 4-x^2 \ so \ f(3) = 4-(3)^2 = 4- 9 = -5[/tex]
(g -f)(3) = g(3) - f(3) , we got g(3) = 18 and f(3) = -5
(g -f)(3) = 18 - (-5) = 18 + 5 = 23
(g-f)(3) = 23
Expression is (g-f)(3) = g(3) - f(3) = [tex]6(3) - (4-(3)^2))[/tex]
