Question

how many grams of KBrO2 are there in 0.168 moles

Answer 1

Hey There!

Molar mass KBrO2 = 151.0011 g/mol

1 mole KBr --------- 151.0011 g

So in 0.168 moles :

mass = number of moles * molar mass

mass = 0.168 * 151.0011

mass = 25.36 g of KBrO2