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HI = 3.9 and HJ = 6.2. Find IJ
JI = 25 and HI = 13. Find HJ
H is the midpoint of IJ and IH = 0.75. Find HJ
H is the midpoint of IJ and IJ = 9.4. Find IH

Respuesta :

calculista

Answer:

Part 1) [tex]IJ=2.3\ units[/tex]

Part 2) [tex]HJ=12\ units[/tex]

Part 3) [tex]HJ=0.75\ units[/tex]

Part 4) [tex]IH=4.7\ units[/tex]

Step-by-step explanation:

Part 1) HI = 3.9 and HJ = 6.2. Find IJ

we have that

I is between H and J

[tex]HJ=HI+IJ[/tex]

substitute the given values and solve for IJ

[tex]6.2=3.9+IJ[/tex]

subtract 3.9 both sides

[tex]6.2-3.9=IJ[/tex]

[tex]2.3=IJ[/tex]

Rewrite

[tex]IJ=2.3\ units[/tex]

Part 2) JI = 25 and HI = 13. Find HJ

we have that

H is between I and J

[tex]IJ=IH+HJ[/tex]

remember that

IH=HI  and IJ=JI

substitute the given values and solve for HJ

[tex]25=13+HJ[/tex]

subtract 13 both sides

[tex]25-13=HJ[/tex]

[tex]12=HJ[/tex]

Rewrite

[tex]HJ=12\ units[/tex]

Part 3) H is the midpoint of IJ and IH = 0.75. Find HJ

we have that

H is between I and J and H is the midpoint  of IJ

so

[tex]IJ=IH+HJ[/tex]

[tex]IH=HJ[/tex] ----> because H is the midpoint

we have

[tex]IH=0.75\ units[/tex]

therefore

[tex]HJ=0.75\ units[/tex]

Part 4) H is the midpoint of IJ and IJ = 9.4. Find IH

we have that

H is between I and J and H is the midpoint  of IJ

so

[tex]IJ=IH+HJ[/tex] -----> equation A

[tex]IH=HJ[/tex] ----> equation B

substitute equation B in equation A

[tex]IJ=2(IH)[/tex]

substitute the given value and solve for IH

[tex]9.4=2(IH)[/tex]

Divide by 2 both sides

[tex]IH=4.7\ units[/tex]

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