What is the equation of the lines that passes through the points (-2, -3) and (4, -5)?
A) y= -1/3x-3
B) y= -4x-11/3
C) y= 4x+3
D) y= -1/3x-11/3

Respuesta :

Since all the options are in the slope intercept form, we find the equation using the formula,

[tex]y = mx + c[/tex]
We can find m, the slope using the formula,

[tex]m = \frac{ change \: in \: y }{change \: in \: x} [/tex]
[tex]m = \frac{ - 5 - - 3}{4 - - 2} [/tex]
[tex]m = \frac{ - 2}{6} = - \frac{1}{3} [/tex]

On substitution,

[tex]y = - \frac{ 1}{3} x + c[/tex]

We use any of the points, say (-2,-3) to determine the value of c.

[tex] - 3 = - \frac{1}{3} ( - 2) + c[/tex]
[tex]c = - \frac{11}{3} [/tex]

The equation is therefore,

[tex]y = - \frac{1}{3} x - \frac{11}{3} [/tex]

The correct answer is D.
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